题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
a = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]n = int(input())for x in range(len(a)): for y in range(len(a[x])): a[x][y] *= nprint(a)
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
a = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]n = int(input())for x in range(len(a)): for y in range(len(a[x])): a[x][y] *= nprint(a)
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