题解 | #二叉树的镜像#
二叉树的镜像
https://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7
struct TreeNode* Mirror(struct TreeNode* pRoot ) {
// write code here
if(pRoot==NULL)
return pRoot;
Mirror(pRoot->left);
Mirror(pRoot->right);
struct TreeNode* temp;
temp=pRoot->left;
pRoot->left=pRoot->right;
pRoot->right=temp;
return pRoot;
}