9/22蚂蚁第三题构造n*n的数组
类似于广度优先的原理,按左上到右下对角线开始构造数组里的数,按层进行赋值。
#蚂蚁笔试##蚂蚁集团#
package com.test;
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
if (n == 1 || n == 2) {
System.out.println(-1);
return;
}
int count2 = (n * n) / 2;
int count1 = n * n - count2;
int[][] nums = new int[n][n];
nums[0][0] = 1;
nums[1][0] = 1;
nums[0][1] = 1;
count1 -= 3;
for (int i = 2; i < 2 * n - 1; i++) {
for (int j = 0; j <= i; j++) {
if (j >= n || (i - j) >= n) {
continue;
}
if (i < n && (j == 0 || j == i)) {
continue;
}
int k = i - j;
if ((nums[j - 1][k - 1] + nums[j - 1][k] + nums[j][k - 1]) % 2 == 0) {
nums[j][k] = 1;
count1 -= 1;
} else {
nums[j][k] = 2;
count2 -= 1;
}
}
if (i < n) {
if ((nums[1][i - 1] + nums[0][i - 1]) % 2 != 0) {
if (count1 < count2) {
count2 -= 1;
nums[0][i] = 2;
} else {
count1 -= 1;
nums[0][i] = 1;
}
} else {
if (nums[0][i - 1] % 2 == 0) {
nums[0][i] = 2;
count2 -= 1;
} else {
nums[0][i] = 1;
count1 -= 1;
}
}
if ((nums[i - 1][1] + nums[i - 1][0]) % 2 != 0) {
if (count1 < count2) {
count2 -= 1;
nums[i][0] = 2;
} else {
count1 -= 1;
nums[i][0] = 1;
}
} else {
if (nums[i - 1][0] % 2 == 0) {
nums[i][0] = 2;
count2 -= 1;
} else {
nums[i][0] = 1;
count1 -= 1;
}
}
}
}
int num1 = 1;
int num2 = 2;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (nums[i][j] == 1) {
System.out.print(num1);
num1 += 2;
} else {
System.out.print(num2);
num2 += 2;
}
if (j != n - 1) {
System.out.print(" ");
}
}
if (i != n - 1) {
System.out.println();
}
}
}
} #蚂蚁笔试##蚂蚁集团#


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