题解 | #字符串排序#

alph = list('qwertyuiopasdfghjklzxcvbnm')
alph.sort()
while True:
    try:
        a = input()
        d = dict()
        for c in a:
            _ = c.lower()
            if _ not in alph:
                _ = '&'
            if _ not in d:
                d[_] = list()
            d[_].append(c)
        out = list()
        for c in alph:
            if c not in d:
                continue
            out += d[c]
        i = 0
        j = 0
        oo = ''
        for c in a:
            if c.lower() in alph:
                oo += out[i]
                i += 1
            else:
                oo += d['&'][j]
                j += 1
        print(oo)
    except:
        break