题解 | #KiKi和酸奶#
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main()
{
int n, h, m;
int a = 0;
int b = 0;
scanf("%d %d %d", &n, &h, &m);
if (h >= m)
{
printf("%d", --n);
}
else
{
a = m % h;
b = m / h;
if (a != 0)
b++;
if (n - b <= 0)
{
printf("0");
}
else
{
printf("%d", n - b);
}
}
return 0;
}
