题解 | #简单密码#
简单密码
http://www.nowcoder.com/practice/7960b5038a2142a18e27e4c733855dac
利用string建立map对应,利用str.find()
查找索引
#include<iostream>
#include<string>
using namespace std;
int main()
{
string input,output;
cin>>input;
string a={"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"};
string b={"bcdefghijklmnopqrstuvwxyza222333444555666777788899990123456789"};
for(auto x:input)
{
string temp;
temp=b[a.find(x)];
cout<<temp;
}
}