题解 | #二叉树的前序遍历#
二叉树的前序遍历
http://www.nowcoder.com/practice/5e2135f4d2b14eb8a5b06fab4c938635
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param root TreeNode类
* @return int整型一维数组
public int[] preorderTraversal (TreeNode root) {
// write code here
int k = 0;
for(int num : list){
array[k++] = num;
}
return array;
if(root==null){
return;
}
list.add(root.val);
preorder(root.left);
preorder(root.right);
}
}
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param root TreeNode类
* @return int整型一维数组
*/
//存储节点值
List<Integer> list = new ArrayList<>();public int[] preorderTraversal (TreeNode root) {
// write code here
preorder(root);
//将集合转化为数组
int[] array = new int[list.size()];int k = 0;
for(int num : list){
array[k++] = num;
}
return array;
}
//前序遍历
public void preorder(TreeNode root){if(root==null){
return;
}
list.add(root.val);
preorder(root.left);
preorder(root.right);
}
}