一个用C语言写的迷你版2048游戏,只有487个字符
Jay Chan 用 C 语言写的一个迷你版 2048 游戏,只有 487 个字符。来围观吧:
M[16],X=16,W,k;main(){T(system("stty cbreak")
);puts(W&1?"WIN":"LOSE");}K[]={2,3,1};s(f,d,i
,j,l,P){for(i=4;i--;)for(j=k=l=0;k<4;)j<4?P=M
[w(d,i,j++)],W|=P>>11,l*P&&(f?M[w(d,i,k)]=l<<
(l==P):0,k++),l=l?P?l-P?P:0:l:P:(f?M[w(d,i,k)
]=l:0,++k,W|=2*!l,l=0);}w(d,i,j){return d?w(d
-1,j,3-i):4*i+j;}T(i){for(i=X+rand()%X;M[i%X]
*i;i--);i?M[i%X]=2<<rand()%2:0;for(W=i=0;i<4;
)s(0,i++);for(i=X,puts("\e[2J\e[H");i--;i%4||
puts(""))printf(M[i]?"%4d|":" |",M[i]);W-2
||read(0,&k,3)|T(s (1,K[(k>>X)%4]));}//[2048]
下面是其他热心网友给上面程序加了注解:
// Original file by Jay Chan:
// https://gist.github.com/justecorruptio/9967738
#include <stdio.h>
#define GRID_LEN 16
int M[GRID_LEN];
int X = GRID_LEN;
int W;
int k;
int K[] = {2, 3, 1};
s(f, d, i, j, l, P) {
for(i = 4; i--;) {
for(j = k = l = 0; k < 4;) {
if(j < 4) {
P = M[w(d, i, j++)];
W |= P >> 11;
l * P && (f ? M[w(d, i, k)] = l << (l == P) : 0, k++);
l = l ? (P ? (l-P ? P : 0) : l) : P;
}
else {
f ? M[ w(d, i, k) ] = l : 0;
++k;
W |= 2 * !l;
l = 0;
}
}
}
}
int w(d, i, j) {
// Decrements until d reaches 0
// Recursive function
if(d <= 0) {
return 4 * i + j;
}
return w(d - 1, j, 3 - i);
}
T(i) {
for(i = X + rand() % X; M[i % X] * i; i--);
i ? M[i % X] = 2 << rand() % 2: 0;
for(W = i = 0; i < 4; i++) {
s(0, i);
}
// Prints the tiles onto the terminal
for(i = X, puts("\e[2J\e[H"); i--; i % 4 || puts("")) {
printf(M[i] ? "%4d|":" |", M[i]);
}
// Read input from keyboard
W - 2 || read(0, &k, 3) | T(s (1, K[(k >> X) % 4]));
}
int main() {
// Uses stty to clear the screen in preparation for the game
T(system("stty cbreak"));
// Game has finished by this point
// If win, display "WIN". Otherwise, display "LOSE".
puts(W & 1 ? "WIN" : "LOSE");
return 0;
}
//[2048]
转自伯乐在线
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