题解 | #字符串字符匹配#

用Set走捷径！把短字符串的字符加入到Set中，把长字符的字符从Set中剔除，如果最后Set为空，则满足条件。

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in.hasNext()) { 
            String shortstr = in.nextLine();
            String longstr = in.nextLine();
            Set<Character> set = new HashSet<>();
            for(int i=0;i<shortstr.length();++i){
                set.add(shortstr.charAt(i));
            }
            for(int i=0;i<longstr.length();++i){
                set.remove(longstr.charAt(i));
            }
            System.out.println(set.size()==0);
        }
    }
}