题解 | #牛客每个人最近的登录日期(二)#
牛客每个人最近的登录日期(二)
http://www.nowcoder.com/practice/7cc3c814329546e89e71bb45c805c9ad
with t_lastday as(
select user_id,client_id,date
from login
where user_id in (
select user_id
from login
group by user_id
having date=max(date)
)
)
select u.name as u_n,c.name as c_n,date
from t_lastday t
left join user u
on t.user_id = u.id
left join client c
on t.client_id = c.id
order by u.name
