题解 | #提取不重复的整数#

#include<iostream>
#include<string>
#include<vector>

using namespace std;

int main(void){
    string s;
    cin >> s;
    string s1;
    for (int i = s.size()-1; i>=0 ;i--){
        s1.push_back(s[i]);
        
        for(int j=0;j<s1.size()-1;j++){
            if(s1[j]==s[i]){
                s1.pop_back();
            }
        }
    }
    
    cout << s1;
    
    return 0;
}