题解 | #字符串排序#
删除字符串中出现次数最少的字符
http://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
s = input()
temp_dict = {}
for i in s:
n = s.count(i)
temp_dict[i] = n
min_count = sorted(temp_dict.values())[0]
delete = []
for i in temp_dict.keys():
if temp_dict[i] == min_count:
# temp_dict.pop(i)
delete.append(i)
for i in s:
if i not in delete:
print(i, end="")