题解 | #尼科彻斯定理#
尼科彻斯定理
http://www.nowcoder.com/practice/dbace3a5b3c4480e86ee3277f3fe1e85
#include <cstdio>
using namespace std;
int main() {
int n;
while (EOF != scanf("%d", &n)) {
int start = n * (n - 1) + 1;
printf("%d", start);
for(int i=1; i<n; i++) {
start += 2;
printf("+%d", start);
}
printf("\n");
}
return 0;
}
