题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
http://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
n = list(map(int, input().split(' ')))
lk_raw = n[2:-1]
lst = [n[1]]
for i in range(len(lk_raw)):
if i%2 != 0:
if lk_raw[i] in lst:
lst.insert(lst.index(lk_raw[i])+1, lk_raw[i-1])
else:
lst.append(lk_raw[i-1])
lst.remove(n[-1])
output = [str(i) for i in lst]
output = ' '.join(output)
print(output)
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