题解 | #实现二叉树先序,中序和后序遍历#
实现二叉树先序,中序和后序遍历
http://www.nowcoder.com/practice/a9fec6c46a684ad5a3abd4e365a9d362
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* }
*/
public class Solution {
/**
*
* @param root TreeNode类 the root of binary tree
* @return int整型二维数组
*/
public int[][] threeOrders (TreeNode root) {
// write code here
List<Integer> list1 = new ArrayList<>();
List<Integer> list2 = new ArrayList<>();
List<Integer> list3 = new ArrayList<>();
preOrder(root, list1);
inOrder(root, list2);
postOrder(root, list3);
int[][] res = new int[3][list1.size()];
res[0] = list1.stream().mapToInt(Integer::valueOf).toArray();
res[1] = list2.stream().mapToInt(Integer::valueOf).toArray();
res[2] = list3.stream().mapToInt(Integer::valueOf).toArray();
return res;
}
private static void preOrder(TreeNode root, List<Integer> list){
if(root == null){
return;
}
list.add(root.val);
preOrder(root.left, list);
preOrder(root.right, list);
}
private static void inOrder(TreeNode root, List<Integer> list){
if(root == null){
return;
}
inOrder(root.left, list);
list.add(root.val);
inOrder(root.right, list);
}
private static void postOrder(TreeNode root, List<Integer> list){
if(root == null){
return;
}
postOrder(root.left, list);
postOrder(root.right, list);
list.add(root.val);
}
}