题解 | #跳台阶#
跳台阶
http://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
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# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
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# @param number int整型
# @return int整型
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class Solution:
def jumpFloor(self , number: int) -> int:
# write code here
dp = [(i+1) for i in range(number)]
for i in range(2, number):
dp[i] = dp[i-2] + dp[i-1]
return dp[number-1]