题解 | #汽水瓶#
汽水瓶
http://www.nowcoder.com/practice/fe298c55694f4ed39e256170ff2c205f
# 递归
def change(num):
ch = num // 3 # 可换的瓶子
a = num // 3 + num % 3 # 换完后的空瓶
if a < 2:
ch += 0
elif a == 2:
ch += 1
else:
ch += change(a)
return int(ch)
while True:
n = int(input())
if n == 0:
break
print(change(n))
