题解 | #求int型正整数在内存中存储时1的个数#

#include<iostream>
using namespace std;
int main()
{
    int n;
    int count = 0;
    while(cin >> n)
    {
        while(n){
        if(n%2)
        {
            count++;
            n = n/2;
        }else{
            n = n/2;
        }
    }
    }
    cout<<count<<endl;
    return 0;
}