题解 | #字符串的排列#
字符串的排列
http://www.nowcoder.com/practice/fe6b651b66ae47d7acce78ffdd9a96c7
# -*- coding:utf-8 -*- class Solution: def Permutation(self, ss): # write code here ans=[] def dfs(index,s,strs): if index==len(ss): ans.append(strs) return for i in range(len(s)): dfs(index+1,s[:i]+s[i+1:],strs+s[i]) dfs(0,ss,"") ans=list(set(ans)) return ans