题解 | #二叉树根节点到叶子节点和为指定值的路径# C++ 解法,迷惑求助,牛客全局变量还得初始化?
二叉树根节点到叶子节点和为指定值的路径
http://www.nowcoder.com/practice/840dd2dc4fbd4b2199cd48f2dadf930a
题解 | #二叉树根节点到叶子节点和为指定值的路径#
C++ 解法,迷惑求助,牛客全局变量还得初始化?
/**
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* };
*/
class Solution {
public:
/**
*
* @param root TreeNode类
* @param sum int整型
* @return int整型vector<vector<>>
*/
vector<vector<int> > ans;
vector<int> path;
int curSum = 0; // What happened? Why should I initialize the global variable? If not, defeat.
void preOrder(TreeNode *node, int sum) {
path.push_back(node->val);
curSum += node->val;
if (!node->left && !node->right && curSum == sum) ans.push_back(path);
if (node->left) preOrder(node->left, sum);
if (node->right) preOrder(node->right, sum);
path.pop_back();
curSum -= node->val;
return ;
}
vector<vector<int> > pathSum(TreeNode* root, int sum) {
if (root == nullptr) return ans;
preOrder(root, sum);
return ans;
}
}; 

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