深度优先搜索+回溯解决网格问题
class Solution {
public boolean exist(char[][] board, String word) {
char[] words = word.toCharArray();
int[][] flag = new int[board.length][board[0].length];
for(int i = 0; i < board.length; i++){
for(int j = 0; j < board[0].length; j++){
if(dfs(board, i, j, words, 0, flag)){
return true;
}
}
}
return false;
}
public boolean dfs(char[][] board, int r, int c, char[] words, int len, int[][] flag){
if(r < 0 || r >= board.length || c < 0 || c >= board[0].length || words[len] != board[r][c] || flag[r][c] == 1){
return false;
}
//终止条件
if(len == words.length - 1){
return true;
}
//进行标记
flag[r][c] = 1;
//回溯
if(dfs(board, r+1, c, words, len+1, flag) || dfs(board, r, c+1, words, len+1, flag) || dfs(board, r-1, c, words, len+1, flag) || dfs(board, r, c-1, words, len+1, flag))
return true;
//进行撤销
flag[r][c] = 0;
return false;
}
}字节算法题解 文章被收录于专栏
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