实习广场投递简历(三)
实习广场投递简历分析(三)
http://www.nowcoder.com/questionTerminal/83f84aa5c32b4cf5a75558d02dd7743c
select job,DATE_FORMAT(date, '%Y-%m') as mon,sum(num) as cnt from resume_info where date >'2025-01-01' and date <'2025-12-31' group by job,mon order by mon desc, cnt desc ;
那么我们借鉴这个写出2026年的:
select job,DATE_FORMAT(date, '%Y-%m') as mon,sum(num) as cnt from resume_info where date >'2026-01-01' and date <'2026-12-31' group by job,mon连接这2个表，然后job相等，并且月份相等，月份相等我们可以使用right函数，这个函数是取右边几个字符，这里取出右边2个字符，相等，最后写出:
select first_year.job,first_year.mon as first_year_mon,first_year.cnt as first_year_cnt,second_year.mon as second_year_mon,second_year.cnt as second_year_cnt from (select job,DATE_FORMAT(date, '%Y-%m') as mon,sum(num) as cnt from resume_info where date >'2025-01-01' and date <'2025-12-31' group by job,mon) first_year join (select job,DATE_FORMAT(date, '%Y-%m') as mon,sum(num) as cnt from resume_info where date >'2026-01-01' and date <'2026-12-31' group by job,mon) second_year on first_year.job=second_year.job and right(first_year.mon,2)=right(second_year.mon,2) order by first_year.mon desc, first_year.job desc ;
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