PAT甲级真题——1008 Elevator （20 分）

1008 Elevator （20 分）

The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.
For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100.

Output Specification:

For each test case, print the total time on a single line.

Sample Input:

3 2 3 1

Sample Output:

41

题目大意：

电梯按照指令上下移动，向上每层6秒，向下每层4秒，每次停下5秒。

题目解析：

按照题意实现即可，注意可能有相邻数字相同的情况。

具体代码：

#include<iostream>

using namespace std;

int main()
{
    int n,now_floor=0,next_floor,time=0;
    cin>>n;
    while(n--){
    	cin>>next_floor;
    	if(next_floor>now_floor)//上楼
		{
			time+=(next_floor-now_floor)*6+5;
			now_floor=next_floor;
		}
    	else if(next_floor<now_floor)
    	{
			time+=(now_floor-next_floor)*4+5;
			now_floor=next_floor;
		}
		else
			time+=5;
	}
	cout<<time;
    return 0;
}