闰年个数(非循环)
#include <stdio.h>
int main()
{
int n, i, count = 0, test;
scanf("%d", &n);
for (i = 1; i <= n; ++i)// 循环版
{
if (i % 4 == 0 && i % 100 != 0 || i % 400 == 0)
{
++count;
}
}
// 非循环
test = n / 4 - n / 100 + n / 400;// 直接算闰年个数，不用循环
printf("test: %d\ncount: %d", test, count);
return 0;
}========================================Talk is cheap, show me the code=======================================
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